Friday, November 18, 2016

Bryans to face Kontinen-Peers in semis of ATP Finals

The Bryan twins conduct an on-court interview after
their first-round victory in the U.S. Open on Aug. 31.
Photo by Paul Bauman
   Third-seeded Bob and Mike Bryan, ex-Stanford stars originally from Camarillo in the Los Angeles area, will face fifth-seeded Henri Kontinen of Finland and John Peers of Australia on Saturday in the semifinals of the ATP World Tour Finals in London.
   Tennis Channel will televise the match live at 4 a.m. PST.
   Kontinen and Peers beat top-seeded Pierre-Hughes Herbert and Nicolas Mahut of France 6-7 (5), 6-4, 10-4 today to finish 3-0 in the Fleming/McEnroe Group and extend their winning streak to eight matches.
   The 38-year-old Bryan twins completed round-robin play in the Edberg/Jarryd Group on Thursday with a 2-1 record.
   In Saturday's other semifinal, second-seeded Jamie Murray of Great Britain and Bruno Soares of Brazil will meet seventh-seeded Raven Klaasen of South Africa and Rajeev Ram of Carmel, Ind., not before 10 a.m. PST (Tennis Channel).
   Kontinen and Peers defeated the Bryans 6-4, 6-2 two weeks ago in the quarterfinals of the BNP Paribas Masters in Paris en route to the title.
   The Bryans have won four titles in the ATP World Tour Finals (2003 and 2004 in Houston, 2009 in Shanghai and 2014 in London) and a record 16 Grand Slam men's doubles crowns. But they have not won a major since the 2014 U.S. Open or reached a final in any tournament since losing to Feliciano Lopez and Marc Lopez (no relation) of Spain in the French Open in June.
   The ATP World Tour Finals consists of the top eight singles players of the year and the top eight doubles teams.

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